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In a neutralization reaction, how many moles of H2SO4 react with 1.5 mole of Al(OH)3? Type in your work below to show how you arrived at your answer. You must show your work, report your answer with the correct number of significant figures and units and include the balanced equation you used for the calculation for full credit.

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Final answer:

In a neutralization reaction, 1.5 moles of Al(OH)3 will react with 4.5 moles of H2SO4.

Step-by-step explanation:

In a neutralization reaction, the moles of acid and base react in a 1:1 molar ratio according to the balanced chemical equation. So, in order to determine the number of moles of H2SO4 that react with 1.5 moles of Al(OH)3, we need to write and balance the equation for the neutralization reaction:

Al(OH)3 + 3H2SO4 → Al(SO4)3 + 6H2O

From the balanced equation, we can see that for every 1 mole of Al(OH)3, 3 moles of H2SO4 react. Therefore, 1.5 moles of Al(OH)3 would react with (1.5 moles) x (3 moles H2SO4 / 1 mole Al(OH)3) = 4.5 moles of H2SO4.

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