Question

In AEFG, e = 9.8 cm, f = 3 cm and G=167º. Find the length of g, to the nearest 10th

of a centimeter.

Answer 1

g = 12.7 cm

Explanation:

Here, we want to find the length of the side g

To do this, we shall employ the use of the cosine rule

Mathematically, by using the general form of the rule, we have it that ;

g^2 = e^2 + f^2 -2efCosG

So we have;

g^2 = (9.8)^2 + (3)^2 - 2(9.8)(3) cos 167

g^2 = 162.33

g = √162.33

g = 12.7