The radius of curvature of a concave mirror determines its curve and reflection. For a mirror with a radius of 0.8m, it would have a focal length of 0.4m. An object 0.2m high placed 0.8m in front of the mirror produces an inverted image that is 0.1m high and located at -0.4m.
The radius of curvature of a concave mirror is the distance between the mirror's surface and its focal point. This distance determines the mirror's curve and how it reflects light. The mirror equation is 1/f = 1/u + 1/v, where 'f' is the focal length, 'u' is the object distance, and 'v' is the image distance. In a concave mirror, the focal length is half the radius of curvature.
Given that our radius of curvature (R) is 0.8m, the mirror's focal length (f) will be R/2 = 0.4m. Substituting f = 0.4m and u = -0.8m (the negative sign denotes that the object is on the same side as the light being reflected), we find v = -0.4m indicating the image is on the same side as the object and inverted. The magnification (m) is given by m = -v/u where v is the image distance and u is the object distance, substituting our values gives us -0.5, hence the image is reduced in size and negative indicates that the image is inverted. Therefore, in this case, an object 0.2m high would produce an image that is 0.1m high and inverted.
Learn more about Concave Mirror