Answer:
f(3) = 4
Explanation:
using the recursive function f(n) = 2 + f(n - 1) with f(1) = 0 , then
f(1) = 0
f(2) = 2 + f(2 - 1) = 2 + f(1) = 2 + 0 = 2
f(3) = 2 + f(3 - 1) = 2 + f(2) = 2 + 2 = 4
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