Question

Evaluate each function:

w(n) = n² +5; find w(10)

w(x) = 2x - 1/3; find w(-7/4)

k(n) = n² + 5/4; find k(7/4)

k(x) = x² + 4x; find k(7)

Answer 1

Task :

• Evaluation of the given functions

Solution:

#1

• w(n) = n² + 5

Hence,

• w(10) = 10² + 5
• w(10) = 100 + 5
• w(10) = 105

#2

• w(x) = 2x -1/3

Hence,

• w(-7/4) = 2(-7/4) - 1/3
• w(-7/4) = -7/2 - 1/3
• w(-7/4) = -21 - 2/6
• w(-7/4) = -23/6 or -3 5/6

#3

• k(n) = n² + 5/4

Hence,

• k(7/4) = (7/4)² + 5/4
• k(7/4) = 49/16 + 5/4
• k(7/4) = 49 + 20/16
• k(7/4) = 69/16 or 4 5/16

#4

• k(x) = x² + 4x

Hence,

• k(7) = 7² + 4*7
• k(7) = 49 + 28
• k(7) = 77