Find the length of a rectangle, given that the perimeter is 180 feet and the length is 5 times the width.

Question

asked Nov 3, 2024 128k views

1 Answer

Oana · Answer 1 · 2024-11-08T02:21:52+0000

Let us consider the width of the rectangle be 'x' feet and length be '5x' feet .

Also the perimeter of the rectangle is 180 feet

${\boxed{\sf{Perimeter = 2(l +w)}}}$

where, l is length and w is width

$\hookrightarrow \sf 2(5x + x ) = 180$

$\hookrightarrow \sf 10x + 2x = 180$

$\hookrightarrow \sf 12x = 180$

Divide both sides by 12,

$\hookrightarrow \sf x = 15$

Hence, width of rectangle = x = 15 feet

$\hookrightarrow \sf Length = 5x$

$\hookrightarrow \sf Length = 5(15)$

$\hookrightarrow \sf Length = 75 \: feet$

Henceforth, the length of the rectangle is 75 feet.