Im so stuck please help!

Question 1

Question 2

Answer:

$\sf\\\textsf{The sum of interior angles of any polygon of 'n' number of sides is given by:}\\(n-2)*180^o$

$\sf\\\textsf{For example, a triangle is a polygon with 3 sides. So,}\\\textsf{Sum of interior angles of triangle}=(3-2)* 180^o=180^o$

$\sf\\\textsf{Pentagon has 5 number of sides.}\\\therefore\ \textsf{Sum of interior angles}=(5-2)* 180^o=540^o$

$\sf\\\textsf{This will help us to find the value of x}^o\textsf{ because the angles shown in the figure }\\\textsf{sums upto 540}^o.$

$\sf\\\therefore\ 90^o+110^o+140^o+122^o+x^o=540^o\\\textsf{or, }462^o+x^o=540^o\\\textsf{or, }x^o=78^o$

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