Question

For the function f(x)=−7x^3−8x+2x^2, Step 1 of 2 : Find the slope of the tangent line at x=1.

Answer 1

The slope of the tangent line at x = 1 is -25.

Explanation:

We are given the function:

`f(x)=-7x^3-8x+2x^2`

And we want to find the slope of the tangent line at x = 1.

The slope of the tangent line at a point for a function is given by its derivative. Find the derivative of the function:

`f'(x)=-21x^2+4x-8`

Then the slope of the tangent line at x = 1 is:

`f'(1)=-21(1)^2+4(1)-8=-25`