Question

Find the zeros of the quadratic function: y = 6x2 x – 35. question 18 options: a) (–5,0), (7,0) b) (–7,0), (5,0) c) (–7∕3,0), (5∕2,0) d) (–5∕2,0), (7∕3,0)

Answer 1

The zeros of the quadratic function y = 6x^2 - 35 are approximately -5/2 and 7/3.

Step-by-step explanation:

The equation is given as y = 6x^2 - 35. To find the zeros of the quadratic function, we set y equal to zero and solve for x:

0 = 6x^2 - 35

6x^2 - 35 = 0

To solve the quadratic equation, we can use the quadratic formula: x = (-b ± sqrt(b^2 - 4ac))/(2a). In this equation, a = 6, b = 0, and c = -35. Substituting these values into the quadratic formula gives us:

x = (-0 ± sqrt(0^2 - 4(6)(-35)))/(2(6))

Simplifying and solving the equation:

x = (± sqrt(840))/12

x = ± sqrt(840)/12

x = ± sqrt(14*60)/12

x = ± sqrt(14)/12 * sqrt(60)/1

x = ± sqrt(14)/12 * sqrt(4*15)/1

x = ± sqrt(14)/12 * 2 sqrt(15)/1

x = ± (2 sqrt(210) /12

x = ± sqrt(210) / 6

So the zeros of the quadratic function are approximately -5/2 and 7/3.