Question

A 1.575 g sample of a new organic material is combusted in a bomb calorimeter. The temperature of the calorimeter and its contents increase from 24.39 °C to 29.88 °C.

The heat capacity (calorimeter constant) of the calorimeter is 42.93 kJ/ °C, what is the heat of combustion per gram of the material?
heat of combustion:
kJ/g

Answer 1

The heat of combustion per gram of the material is 151.45 kJ/g.

Step-by-step explanation:

To calculate the heat of combustion per gram of the organic material, we need to use the equation q = m * C * ΔT, where q is the heat energy, m is the mass of the material, C is the heat capacity of the calorimeter, and ΔT is the change in temperature. First, let's calculate the heat energy q:

q = 42.93 kJ/°C * (29.88 °C - 24.39 °C) = 238.4 kJ

Next, we divide the heat energy by the mass of the material:

Heat of combustion = q / 1.575 g = 151.45 kJ/g