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What is the resulting acceleration of a 100-kg object if 1,000 N of force is applied to it and it is opposed by a force of kinetic friction equivalent to 100.0 N?

What is the resulting acceleration of a 100-kg object if 1,000 N of force is applied to it and it is opposed by a force of kinetic friction equivalent to 100.0 N?
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What is the resulting acceleration of a 100-kg object if 1,000 N of force is applied to it and it is

opposed by a force of kinetic friction equivalent to 100.0 N?

User Jenya
by
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1 Answer

3 votes
F1 = 1000 N
F2 = 100 N
F = F1 - F2 = 900 N
m = 100 kg

ma = F
a = F/m = 900/100
a = 9 m/s^2
User Mihkel
by
8.1k points
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