Pt = 4x + 9 and tq = 6x - 7 what is the value of pt

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Kaps Hasija · Answer 1 · 2024-11-26T12:51:49+0000

Answer:

pt = 41

Explanation:

Let, pt = tq

$\hookrightarrow 4x + 9 = 6x - 7$

Subtract 9 from both sides,

$\hookrightarrow 4x + 9 -9 = 6x - 7 - 9$

$\hookrightarrow 4x = 6x - 16$

Subtract 6x from both sides,

$\hookrightarrow 4x - 6x = 6x - 16 - 6x$

$\hookrightarrow -2x = -16$

Divide both sides by -2

$\hookrightarrow x = 8$

Now Plug the value of x in pt.

since pt = 4x + 9

$\hookrightarrow pt = 4(8) + 9$

$\hookrightarrow pt = 32 + 9$

$\hookrightarrow pt = 41$

Henceforth the value of pt is 41

$\dotfill$

Pt = 4x + 9 and tq = 6x - 7 what is the value of pt

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