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If r(x)=4x^2-3x+7, Find r(2a^2)

User Yots
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1 Answer

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19 votes

Answer:

r(2a²) = 16a⁴ - 6a² + 7

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Algebra I

  • Functions
  • Function Notation
  • Exponential Rule [Powering]:
    \displaystyle (b^m)^n = b^(m \cdot n)

Explanation:

Step 1: Define

Identify

r(x) = 4x² - 3x + 7

Step 2: Evaluate

  1. Substitute in x [Function r(x)]: r(2a²) = 4(2a²)² - 3(2a²) + 7
  2. Exponential Rule [Powering]: r(2a²) = 4(2²a²⁽²⁾) - 3(2a²) + 7
  3. [Exponents] Multiply: r(2a²) = 4(2²a⁴) - 3(2a²) + 7
  4. Exponents: r(2a²) = 4(4a⁴) - 3(2a²) + 7
  5. Multiply: r(2a²) = 16a⁴ - 6a² + 7
User Stenehall
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