Question

What quantity of pure acid must be added to 300 mL of a 50% acid solution to produce a 60% acid solution?​

Answer 1

To produce a 60% acid solution, no quantity of pure acid can be added to a 300 mL of 50% acid solution.

Step-by-step explanation:

To find the quantity of pure acid that must be added to 300 mL of a 50% acid solution to produce a 60% acid solution, we can use a simple dilution formula:

C1V1 = C2V2

Where:

C1 = initial concentration of the acid solution

V1 = initial volume of the acid solution

C2 = final concentration of the acid solution

V2 = final volume of the acid solution

Plugging in the given values:

0.5 * 300 = 0.6 * (300 + V)

Simplifying the equation:

150 = 180 + 0.6V

0.6V = -30

V = -50

Since volume cannot be negative, no quantity of pure acid can be added to achieve the desired concentration. The question might have a typo or error in the given information