Answer:
A' = (0,0)
B' = (6,-12)
C' = (-12,-12)
Explanation:
According to the Question,
- Let's label the corner points of the triangle A,B,C starting at the origin and moving clockwise(ForDiagram Please Find in Attachment)
A = (0,0) , B = (2,-4) , C = (-4,-4)
- Dilating with a scale factor 3 means we multiply each coordinate of each point by the value 3
A = (0,0) becomes A' = (0,0). No change happens. This point is fixed
B = (2,-4) becomes B' = (6,-12). This point does move
C = (-4,-4) becomes C' = (-12,-12). This moves as well
So all you need to do from here is draw triangle A'B'C'.
Note ⇒
- the lengths of triangle A'B'C' are Thrice as long as their counterparts on triangle ABC.
- Consequently, this means the perimeter of A'B'C' is Thrice as long as the perimeter of ABC.
- Also, triangle A'B'C's area is Nine times larger than the area of triangle ABC.