Question

A portion of the quadratic formula proof is shown. Fill in the missing statement. Statements Reasons x squared plus b over a times x plus the quantity b over 2 times a squared equals negative 4 times a times c all over 4 times a squared plus b squared over 4 a squared Find a common denominator on the right side of the equation x squared plus b over a times x plus the quantity b over 2 times a squared equals b squared minus 4 times a times c all over 4 times a squared Add the fractions together on the right side of the equation the quantity x plus b over 2 times a squared equals b squared minus 4 times a times c all over 4 times a squared Rewrite the perfect square trinomial on the left side of the equation as a binomial squared x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c, all over 4 times a squared Take the square root of both sides of the equation x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c, all over 2 times a Simplify the right side of the equation ? Subtract the quantity b over 2 times a from both sides of the equation x equals b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over a x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a x plus b over 2 times a equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a

Answer 1

Answer is 2a I think

Answer 2

Answer: x + b/2a = ± (√(b^2 - 4ac))/(2a)

Explanation:

To fill in the missing statement, we need to simplify the right side of the equation.

The equation we have is x + b/2a = ± √(b^2 - 4ac)/(2a).

To simplify the right side, we can divide both the numerator and denominator by 2a.

This gives us x + b/2a = ± (√(b^2 - 4ac))/(2a).

Therefore, the missing statement is x + b/2a = ± (√(b^2 - 4ac))/(2a).