Answer:
To calculate the resulting force when a steel ball is immersed in water, we need to consider the buoyant force acting on the ball.
The buoyant force is the upward force exerted on an object submerged in a fluid (in this case, water) and is equal to the weight of the fluid displaced by the object. It can be calculated using the following formula:
Buoyant Force = Volume of the fluid displaced × Density of the fluid × Acceleration due to gravity
For a steel ball of radius 0.6 meters immersed in water, we need to know the density of steel and the density of water.
The density of steel varies depending on the type, but on average, it is around 7850 kg/m³.
The density of water is approximately 1000 kg/m³.
Now, let's calculate the volume of the fluid displaced by the steel ball, which is the volume of the steel ball itself.
Volume of the steel ball = (4/3) × π × (radius)³
Volume of the steel ball = (4/3) × π × (0.6)³ ≈ 0.9048 m³
Now, we can calculate the buoyant force:
Buoyant Force = Volume of the fluid displaced × Density of the fluid × Acceleration due to gravity
Buoyant Force = 0.9048 m³ × 1000 kg/m³ × 9.81 m/s² ≈ 8882.15 N
The resulting force acting on the steel ball when immersed in water is approximately 8882.15 Newtons (N) upward. This buoyant force counteracts the weight of the steel ball, allowing it to float or partially float in the water, depending on its overall density.
Step-by-step explanation: