Answer:
To graph the system of equations (+ y -x-2 x-4y=0), we first need to rewrite the equations in slope-intercept form, which is y = mx + b, where m represents the slope and b represents the y-intercept.
Let's start with the first equation: +y - x - 2 = 0. We can isolate y by adding x and 2 to both sides of the equation. This gives us y = x + 2.
Next, let's rewrite the second equation: x - 4y = 0. To isolate y, we need to move the x term to the other side of the equation. So, subtract x from both sides: -4y = -x. Divide both sides by -4 to solve for y: y = (-1/4)x.
Now that we have both equations in slope-intercept form, we can graph them.
For the equation y = x + 2, we can start by plotting the y-intercept, which is 2. This is the point (0, 2) on the graph. From there, we can use the slope, which is 1, to find additional points. Since the slope is 1, we can move 1 unit up and 1 unit to the right to find the next point, and so on.
For the equation y = (-1/4)x, the y-intercept is 0 since there is no constant term. So, we can start by plotting the point (0, 0) on the graph. From there, we can use the slope, which is -1/4, to find additional points. Since the slope is negative, we can move 1 unit down and 4 units to the right to find the next point, and so on.
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