Question

If 24.0 mL of methanol (CH,OH) is dissolved in 55.0 mL of water, determine the percent by volume of methanol in the solution. Name the law or equation that is used to solve this problem. Show your work.

Answer 1

To determine the percent by volume of methanol in the solution, we can use the equation:

Percent by volume = (Volume of methanol / Total volume of solution) * 100

Given that 24.0 mL of methanol is dissolved in 55.0 mL of water:

Percent by volume = (24.0 mL / (24.0 mL + 55.0 mL)) * 100

Percent by volume = (24.0 mL / 79.0 mL) * 100

Percent by volume ≈ 30.38%

The equation used to solve this problem is the percent by volume formula, which calculates the percentage of one component (methanol) in a mixture (solution) based on their respective volumes.