Question

Compound A has molecular formula C4H10. Compound A gives two monochlorides, B and C, on photochemical chlorination. Treatment of either of these monochlorides with potassium tert-butoxide gives the same alkene (C4H8) as the product, but B leads to just one isomer of the alkene, D, whereas C gives D and another isomer of the alkene, E. Treatment of monochlorides B and C with aqueous ethanol gives products F and G, respectively, both of which are of molecular formula C4H10O. What are the chemical names of compounds A-G

Answer 1

Step-by-step explanation:

Radical chlorination of butane in the presence of light gives rise to the formation of two isomeric monochlorides B (1-chlorobutane) and C (2-chlorobutane). Both upon reaction with a bulky base (potassium tert-butoxide) give rise to D(but-1-ene) and E(but-2-ene) respectively, this is because the bulky base abstracts the less hindered proton. Compound B and C were later treated with aqueous C2H5OH which results in the hydrolysis of alkyl halides to produce Compound F(butan-1-ol) and compound G (butan-2-ol) respectively.

The diagrammatic expression of the whole reaction is shown in the attached image below.