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Find (a) the axis of the symmetry and (b) the vertex of the graph of the function. y=-4x^2+16x

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The given function is y = -4x^2 + 16x.

(a) To find the axis of symmetry, we use the formula x = -b/2a, where a = -4 and b = 16.

x = -b/2a = -16/2(-4) = 2

Therefore, the axis of symmetry is x = 2.

(b) To find the vertex, we substitute x = 2 into the given equation and solve for y:

y = -4(2)^2 + 16(2) = -16 + 32 = 16

Therefore, the vertex is (2, 16).

Hence, the axis of symmetry is x = 2 and the vertex is (2, 16).
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