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3 votes
Twice the difference of a number and 2 is at the most 28

2 Answers

7 votes

Answer: x<16

Explanation:

2(x-2) < 28

2x-4 < 28

2x < 32

x < 16

User Redrah
by
8.5k points
2 votes

Final Answer:

  • h ≤ 16

In-depth explanation:

Hi! This question is asking us to find the number, given that:

Twice the difference of a number and 2 is at the most 28.

Let's call the number h.

The difference of h and 2: h - 2

Twice that difference: 2(h - 2)

The symbol for at most is: ≤

Inequality:
\sf{2(h-2)\leqslant28}


\rule{350}{1}

SOLVING FOR H

Distribute 2


\sf{2h-4\leqslant28}

Add 4 to both sides


\sf{2h\leqslant32}

Divide each side by 2


\sf{h\leqslant16}

User Jcmrgo
by
8.3k points

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