Question

how many liters of a 14% alcohol solution must be mixed with 20 liters at a 50% solution to get a 20% solution

Answer 1

100 liters

Explanation:

`0.14x+0.50(20)=0.20(x+20)\\0.14x+10=0.20x+4\\10=0.06x+4\\6=0.06x\\100=x`

Therefore, you would need 100 liters of the 14% alcohol solution.