Question

(3y-18)(y^(2)-25)=0 here is more than one solution,

Answer 1

y = -5, 5, 6

Explanation:

In order to solve the equations, we can separate both as:

`\displaystyle{3y-18=0 \ \: \text{or} \ \: y^2-25=0}\\\\\displaystyle{3y=18 \ \: \text{or} \ \: \left(y-5\right)\left(y+5\right)=0}\\\\\displaystyle{y = 6 \ \: \text{or} \ \: y - 5 = 0 \ \: \text{or} \ \: y + 5 = 0}\\\\\displaystyle{\therefore y = 6, 5, -5}`

Reference of Formulas

`\displaystyle{x^2-y^2=\left(x+y\right)\left(x-y\right)}`

Therefore, there are three solutions which are y = -5, 5, 6