Question

write a Python program that finds all the duplicate numbers in a sequential list of n numbers, count, and print them out.

Answer 1

Certainly! Here's a Python program that finds and prints all the duplicate numbers in a sequential list:

python
def find_duplicates(numbers):
duplicates = []
count = {}

for num in numbers:
if num in count:
count[num] += 1
else:
count[num] = 1

for num, freq in count.items():
if freq > 1:
duplicates.append(num)

return duplicates

# Example usage:
number_list = [1, 2, 3, 4, 5, 4, 3, 2, 6, 7, 7, 8, 9, 9]
duplicate_numbers = find_duplicates(number_list)

print("Duplicate numbers:")
for num in duplicate_numbers:
print(num)


In this program, the find_duplicates function takes a list of numbers as input and uses a dictionary (`count`) to keep track of the frequency of each number. After iterating through the list, it checks for numbers with a frequency greater than 1 and adds them to the `duplicates` list.

Finally, the program prints out the duplicate numbers. In the example usage, the program finds and prints the duplicate numbers in the `number_list` sequence. Feel free to modify the number_list with your own sequence of numbers.

Answer 2

Answer: To write a Python program that finds duplicate numbers in a sequential list, follows these steps:

1. Create a sequential list of numbers:

- Define a list variable and populate it with sequential numbers, either by manually assigning values or using a loop.

2. Find duplicate numbers:

- Initialize an empty list to store the duplicate numbers found.

- Use a loop to iterate through each number in the list.

- For each number, check if it appears more than once in the list by using the `count()` method.

- If the count is greater than 1, it is a duplicate, so append it to the list of duplicates.

3. Count and print the duplicate numbers:

- Use the `len()` function to count the number of elements in the list of duplicates.

- Print the count and the duplicate numbers found.

Here's an example implementation of the Python program:

```python

# Step 1: Create a sequential list of numbers

numbers = [1, 2, 3, 4, 5, 5, 6, 7, 8, 9, 9]

# Step 2: Find duplicate numbers

duplicates = []

for num in numbers:

if numbers.count(num) > 1:

duplicates.append(num)

# Step 3: Count and print the duplicate numbers

count = len(duplicates)

print("Found", count, "duplicate numbers:")

for num in duplicates:

print(num)

```

In this example, the list `numbers` contains duplicate numbers, and the program finds and prints them. You can modify the list `numbers` to test the program with different sequential numbers.

Step-by-step explanation: