Question

A physics major is cooking breakfast when he notices that the frictional force between the steel spatula and the Teflon frying pan is only 0.150 N. Knowing the coefficient of kinetic friction between the two materials (0.04), he quickly calculates the normal force. What is it (in N)

Answer 1

`f_n=3.75N`

Step-by-step explanation:

From the question we are told that:

Frictional force
`F=0.150N`

Coefficient of kinetic friction
`\mu=0.04`

Generally the equation for Normal for is mathematically given by

`f_n=(F)/(\mu)`

Therefore

`f_n=(0.150)/(0.04)`

`f_n=3.75N`