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1. Convert 5.2x10^21 molecules of titanium (iii) hydroxide to mole =s of titanium (iii) hydroxide.

2. Convert 1.56 moles of gold (iii) oxide to molecules of gold (iii) oxide.

1 Answer

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1. To convert 5.2x10^21 molecules of titanium (III) hydroxide to moles, we need to use Avogadro's number, which states that 1 mole of any substance contains 6.022x10^23 molecules.

Given:

Number of molecules = 5.2x10^21

Using the conversion factor:

1 mole = 6.022x10^23 molecules

We can set up the following conversion:

5.2x10^21 molecules x (1 mole / 6.022x10^23 molecules)

Calculating this expression gives:

5.2x10^21 molecules x (1 mole / 6.022x10^23 molecules) ≈ 0.0086 moles

Therefore, 5.2x10^21 molecules of titanium (III) hydroxide is approximately equal to 0.0086 moles of titanium (III) hydroxide.

2. To convert 1.56 moles of gold (III) oxide to molecules, we can use Avogadro's number in the opposite direction:

Given:

Number of moles = 1.56

Using the conversion factor:

1 mole = 6.022x10^23 molecules

We can set up the following conversion:

1.56 moles x (6.022x10^23 molecules / 1 mole)

Calculating this expression gives:

1.56 moles x (6.022x10^23 molecules / 1 mole) ≈ 9.37x10^23 molecules

Therefore, 1.56 moles of gold (III) oxide is approximately equal to 9.37x10^23 molecules of gold (III) oxide.

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