Question

Given: DB_I_ (perpendicular) Prove: (triangle)ADB = (congruent) (triangle) CDB

SEE PHOTO FOR TRIANGLE!!

Answer 1

Explanation:

In the 2Δ's ADB and CDB,

∠DBA=∠DBC=90°(given that DB⊥AC) ⇒R

AB=BC(DB perpendicular bisects AC side) ⇒S

∠A=∠C(given)

∴DA=DC(when considering ADCΔ,if two angles of a Δare equal then the 2 sides opposite to those are equal)⇒H

∴ΔADB≡ΔCDB(R.H.S)

R=right angle,H=hypotenuse,S=side