Answer:
0.000539 moles of H ions
Step-by-step explanation:
Nitric acid is HNO3. It is a strong acid, so we will assume that all of the hydrogens will become H ions (H^+1).
Lets assume 0.183 m is really meant to be 0.183 M
M stand for molar, or moles/liter, so we have a solution that contains 0.183 moles nitric acid per liter.
To find the number of actual moles in 2.945 ml of this solution, we can multiply the volume times the concentration:
Volume x Concentration = moles
(2.945 ml)*(0.183 M) = moles
(2.945 ml)*(0.183 moles/liter) = moles [Use moles/liter for M]
(2.945 ml)*(0.183 moles/liter)*(1 liter/1000 ml) = moles [Add a conversion factor to account for the ml and liter units]
Liters and ml both cancel:
(2.945)*(0.183 moles)*(/1000) = moles HNO3 [ = 0.000539 moles HNO3]
There are 0.000539 moles of HNO3 in 2.945 ml of 0.183 M nitric acid.
Therefore, there are 0.000539 moles of H ions present in the sample.