Question

2x+ 4y =16 -2x- 3y = -6 solve this system of equations using the elimination method

Answer 1

`\large{ \boxed{ \boxed{ \tt{☂ \: OUR \: FINAL \: ANSWER : \underline{ \tt {x = - 12 \: and \: y = 10}}}}}✓}`

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Answer 2

`\small \sf \: x = - 12 \: \: and \: y = 10`

Explanation:

2x + 4y = 16.

-2x - 3y = -6

Add both equation ;

`\small \sf \: \: \: \: \: 2x + 4y = 16 \\ + \small \sf \: \: \underline{ -2x - 3y = -6 }\\ \small \sf \: \: \: \: \: \underline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \ \blue{y = 10}}`

Therefore , y = 10

Substitute the value of y in the first equation

2x + 4 = 16

2 x + 4 × (10) = 16

2x + 40 = 16

subtract 40 from both side

2x + 40 - 40 = 16 - 40

2x = - 24

divide each side by 2

2x/ 2 = - 24 / 2

x = - 12