71,669 views
44 votes
44 votes
A 4.1-kg ball is thrown from the top of a 4-m tall building (point A) with a speed of 1 m/s at an angle 2 degrees above the horizontal. If air resistance is negligible, what is the value of the kinetic energy of the ball as it hits the ground?

User Zzaman
by
2.7k points

1 Answer

27 votes
27 votes

Answer:


K.E = 163 J

Step-by-step explanation:

From the question we are told that:

Mass
m=4.1kg

Height
h=4m

Speed
V=1m/s

Angle
\theta= 2 \textdegree

Generally the equation for K.E is mathematically given by

Since

The potential energy and kinetic energy is equal to the kinetic energy as it hits the ground.

Therefore


K.E=mgH + 0.5mV^2


K.E = (4.1)(9.81)(4) + (4.1)(1)^2*0.5


K.E = 163 J

User Kenyee
by
2.6k points