Question

Write the product as a sum or difference:
6 sin(34r) cos(11r) =

Answer 1

To write the product as a sum or difference, we can use the trigonometric identity:

sin(A) cos(B) = (1/2)[sin(A + B) + sin(A - B)]

Applying this identity to the given expression, we have:

6 sin(34r) cos(11r) = 6 * (1/2)[sin(34r + 11r) + sin(34r - 11r)]

Simplifying further:

6 sin(34r) cos(11r) = 3[sin(45r) + sin(23r)]