Question

a parallelogram has one side at (-4, 1) and (-7, 2) and the other side is at (-3, 4) and (-6, 5). what are the lengths of the sides and the slopes of the sides?

Answer 1

Lengths of sides:

√((-7 - (-4)² + (2 - 1)²) = √((-3)² + 1²) = √(9 + 1)

= √10

√((-7 - (-3)² + (2 - 4)²) = √((-4)² + (-2)²)

= √(16 + 4) = √20 = 2√5

Slopes of sides:

(-7 - (-4))/(2 - 1) = -3

(-7 - (-3))/(2 - 4) = -4/-2 = 2

The lengths of the sides are √10 and 2√5, and the slopes of the sides are -3 and 2.