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6 votes
6 votes
A cell has an emf of 1.5 V and an internal resistance of 0.65 Q.

The cell is connected to a resistor R.
[0[8].[4] State what is meant by an emf of 1.5 V.
[2 marks]
I
[0] 8]-[2] The current in the circuit is 0.31 A.
Show that the total power output of the cell is approximately 0.47 W.
[1 mark]
[o[s).[3] Calcutate the energy dissipated per second in resistor R.
[2 marks]
energy dissipated per second = Ist
[o[si.[4] The cell stores 14 kJ of energy when it is fully charged. The cell's emf and internal resistance are constant as the cell f discharged.
Calculate the maximum time during which the fully-charged cell can deliver energy to
resistor R.
[2 marks)
maximum time = 5

User SHM
by
2.4k points

1 Answer

26 votes
26 votes

Answer:

14000 J / 0.40 J/s = 35 000 s or about 9.75 hrs

User Rahul Manne
by
3.0k points