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What a the subject of the formula
t^2 = 2p + as

User Clarkk
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1 Answer

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Answer:


\sf a = (t^2-2p)/(s)

Explanation:

To make 'a' as the subject:

t² = 2p + as

  • Isolate the term containing 'a'. Subtract 2p from both sides.

t² - 2p = as

  • Divide both sides by 's'.


\sf (t^2 - 2p)/(s)=(as)/(s)\\\\\\(t^2-2p)/(s)=a\\\\\boxed{\bf a =(t^2-2p)/(s)}

User Wrozwad
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