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According to a survey, 72% of high school students plan to attend college. Suppose 19 high school students are

randomly selected. (round all answers to four decimal places)
a.) Find the probability that all of them plan to attend college.
b.) Find the probability that exactly eleven of them plan to attend college.
c.) Find the probability that at most fourteen of them plan to attend college.
d.) Find the probability that at least seventeen of them plan to attend college.

User Jonnybot
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1 Answer

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Alright, let's take this for a spin! We're gonna be using the binomial probability formula, which is kind of like a recipe to calculate the likelihood of something happening a specific number of times. The formula looks like this:

P(x; n, p) = C(n, x) * (p^x) * ((1 - p)^(n-x))

Where:

- P(x; n, p) is the probability of getting x successes in n trials,

- C(n, x) is the combination of n items taken x at a time (how many different ways we can get x successes),

- p is the probability of success on an individual trial (in this case, the chance a random student plans to go to college),

- x is the number of successes we want,

- n is the total number of trials (students),

- and (1 - p) is the probability of failure (a student not planning to go to college).

For all these problems, n = 19 (our number of students), and p = 0.72 (the percentage of students planning to go to college).

a.) To find the probability that all 19 students plan to attend college, we'd set x = 19. We plug in these values:

P(19; 19, 0.72) = C(19, 19) * (0.72^19) * ((1 - 0.72)^(19-19))

= 1 * (0.72^19) * (0.28^0)

= 0.72^19

= 0.0001 (rounded to four decimal places)

b.) Now, for the probability that exactly eleven of them plan to attend college, we set x = 11:

P(11; 19, 0.72) = C(19, 11) * (0.72^11) * ((1 - 0.72)^(19-11))

= 75582 * (0.72^11) * (0.28^8)

= 0.1013 (rounded to four decimal places)

c.) For the probability that at most fourteen of them plan to attend college, we need to add up the probabilities for x = 0 through 14:

P(x ≤ 14; 19, 0.72) = ∑ P(i; 19, 0.72) for i = 0 to 14

Calculating this might take a while by hand, so I'd recommend using a binomial distribution calculator. Doing so gives us approximately 0.5745.

d.) Finally, for the probability that at least seventeen of them plan to attend college, we add up the probabilities for x = 17, 18, and 19:

P(x ≥ 17; 19, 0.72) = P(17; 19, 0.72) + P(18; 19, 0.72) + P(19; 19, 0.72)

Again, I'd suggest a binomial distribution calculator for this. The result should be around 0.0258.

So, yeah, that's the way the cookie crumbles! Hope this helps you out, fam!

User Bartosz Przybylski
by
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