Question

5. How many grams of aluminum phosphate is produced from 7.5 g of lithium phosphate in this balanced equation?

2Li3PO4 + Al2(SO4)3 --> 3Li2SO4 + 2AlPO4

Answer 1

To solve this problem, we need to first convert the grams of lithium phosphate to moles.

Molar mass of Li3PO4 = (6.941 * 3) + (15.999 + 31.999 * 4) = 115.79 g/mol

Moles of Li3PO4 = 7.5 g / 115.79 g/mol = 0.0648 mol

According to the balanced equation, the mole ratio between Li3PO4 and AlPO4 is 2:2. Therefore, we can determine the moles of AlPO4 produced.

Moles of AlPO4 = 0.0648 mol

Finally, we can convert the moles of AlPO4 to grams using its molar mass.

Molar mass of AlPO4 = (26.9815 * 2) + (15.999 + 31.999 * 4) = 121.96 g/mol

Grams of AlPO4 = 0.0648 mol * 121.96 g/mol = 7.93 g

Therefore, 7.93 grams of aluminum phosphate is produced from 7.5 grams of lithium phosphate.