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If a squared plus b squared equals to 40 and ab equals 12 find a plus b and a minus b

User Frnak
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Explanation:


{a}^(2) + {b}^(2) = 40


ab = 12

Notice that


(a + b) {}^(2) = {a}^(2) + 2ab + {b}^(2)


(a - b) {}^(2) = {a}^(2) - 2ab + {b}^(2)

So


2ab = 24


- 2ab = 24

So


(a + b) {}^(2) = 64


a + b = 8

Also,


(a - b) {}^(2) = 16


a - b = 4

User Plimbs
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