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HELP ASAP PLEASE

What is the solution to the equation 16 ^2x -3 . 4^-2x = 4^2?
A. x=4
B. x=-A
C. x=2
D. x=1

User Coursal
by
7.8k points

2 Answers

3 votes

Answer:

The correct answer is,

A. x = 4

Explanation:

We have the equation,


16^(2x)-3(4^(-2x))=4^2

Solving this, we get,


16^(2x-3)(4^(-2x))=4^2\\(4^2)^(2x-3)(4^(-2x))=4^2\\(4^(4x-6))(4^(-2x))=4^2\\4^(4x-2x-6)=4^2\\4^(2x-6)=4^2\\4^(2x)4^(-6)=4^2\\4^(2x)=4^24^6\\4^(2x)=4^(2+6)\\4^(2x)=4^8\\

comparing coefficients,

we get,

2x = 8,

x = 8/2

x = 4

User Ptrico
by
7.3k points
5 votes

x=256/4093 aka 0.06254580991

B

meaning that x is less than answer choices A,C and D meaning ur answer is B

User Daniel Campos
by
8.2k points

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