Answer:
E = V/d = 120 V/0.06 m = 2000 V/m
Now we can calculate the potential energy of the point charge as it moves from point A to point B:
U = qEΔd = (1.0 × 10^-6 C)(2000 V/m)(0.06 m) = 1.2 × 10^-7 J
Therefore, the potential energy decreases by 1.2 × 10^-7 J as the point charge moves from point A to point B. So, option c) The potential energy decreases by 6.0 × 10^-6 J is necessarily true concerning the potential energy of the point charge
Step-by-step explanation:
The potential energy of a charged particle in an electric field is the work done by the electric force in moving the charge from a point where the electric field is zero to a point where the electric field is E. The potential energy is given by the equation: U = qE where q is the charge of the particle and E is the electric field