In the previous question, the minterm expansion of Overflow1 is as follows:Expression for Overflow 1 = m1 + m2 + m3The correct minterms to get credit for this problem are m1, m2 and m3. Therefore, options A, B, C, E, F, G and H are all incorrect. The correct answer is D. m3.Now, if the design only allows to use one gate, the gate that can be used for Overflow2 is NAND (D).NAND is a logic gate that produces an output that is the negation of the conjunction of the inputs. It has the property of functional completeness and is one of the two gate universes, which means that any logical function can be implemented using a combination of NAND gates. Therefore, if only one gate is allowed to be used, the gate that can be used for Overflow2 is NAND (D).