63.2k views
4 votes
In a chemical reaction, exactly 2 mol of substance A react to produce exactly 3 mol of substance B.

How many molecules of substance B are produced when 29.5 g of substance A reacts? The molar mass of substance A is 15.7 g/mol.
Convert the mass of A to moles
Convert the number of moles of A to the number of moles of B
Convert the number of moles of B to the molecules of B

1 Answer

3 votes

To solve this problem, we'll follow these steps:

1. Convert the mass of substance A to moles.

2. Determine the number of moles of substance B using the stoichiometric ratio.

3. Convert the number of moles of substance B to molecules.

Step 1: Convert the mass of A to moles

Given:

Mass of substance A = 29.5 g

Molar mass of substance A = 15.7 g/mol

Number of moles of A = Mass of A / Molar mass of A

Number of moles of A = 29.5 g / 15.7 g/mol

Number of moles of A ≈ 1.875 mol

Step 2: Determine the number of moles of substance B using the stoichiometric ratio

The given ratio states that 2 moles of A react to produce 3 moles of B.

Number of moles of B = (Number of moles of A) * (Moles of B / Moles of A)

Number of moles of B = 1.875 mol * (3 mol B / 2 mol A)

Number of moles of B ≈ 2.8125 mol

Step 3: Convert the number of moles of substance B to molecules

To convert moles to molecules, we need to use Avogadro's number, which states that 1 mole of any substance contains approximately 6.022 x 10^23 molecules.

Number of molecules of B = (Number of moles of B) * (Avogadro's number)

Number of molecules of B = 2.8125 mol * (6.022 x 10^23 molecules/mol)

Number of molecules of B ≈ 1.691 x 10^24 molecules

Therefore, when 29.5 g of substance A reacts, approximately 1.691 x 10^24 molecules of substance B are produced.

User Balasubramanian
by
8.3k points

No related questions found