Final answer:
To express the function f(x) = 2x-4/(x^2-4x+3) as a power series, first factor the denominator and use partial fractions. The power series representation is f(x) = 1/(x-1) + 1/(x-3). The interval of convergence is (-∞, 1) ∪ (1, 3) ∪ (3, ∞).
Step-by-step explanation:
To express the function f(x) = 2x-4/(x^2-4x+3) as the sum of a power series, we first need to factor the denominator and use partial fractions:
x^2-4x+3 = (x-1)(x-3)
Then, we can write the function as:
f(x) = 2x-4/((x-1)(x-3)) = A/(x-1) + B/(x-3)
Now, we can find the values of A and B by equating the numerators:
2x-4 = A(x-3) + B(x-1)
Solving this system of equations, we get A = 1 and B = 1. Therefore, f(x) can be expressed as:
f(x) = 1/(x-1) + 1/(x-3)
To find the interval of convergence for the power series representation, we need to find the values of x for which the series converges. In this case, the interval of convergence is (-∞, 1) ∪ (1, 3) ∪ (3, ∞).