Answer:
j(0, 2)
Explanation:
You want to know the coordinates of point J in parallelogram GBJF, given G(-4, 1), B(-2, 3), F(-2, 0).
Midpoint
In a parallelogram, the diagonals bisect each other. This means their midpoints are the same.
(G +J)/2 = (B +F)/2 = M
G +J = B +F . . . . . . . . multiply by 2
J = B +F -G
J = (-2, 3) +(-2, 0) -(-4, 1)
J = (-2-2+4, 3+0-1) = (0, 2)
The coordinates of point J are (0, 2).
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