Question

If the distance covered by an object in time t is given by s(t)=t²+5t

, where s(t) is in meters and t is in seconds, what is the distance covered in the interval between 1 second and 5 seconds?

Answer 1

To answer that you would take s(5) - s(1)
s(1) = 1^2 + 5(1) = 1 + 5 = 6 (m/s)

s(5) = 5^2 + 5(5) = 25 + 25 = 50 (m/s)

Therefore the distance covered would be:
50 - 6 = 44m/s

The distance in the interval between 1 second and 5 seconds where the distance covered by an object is s(t) = t^2 + 5t is 44m/s