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The length of a rectangle is 4 ft longer than its width. If the perimeter of the rectangle is 32 ft, find its area.

User Kkamil
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To find the area of a rectangle, we need to know its length and width. Let's solve the problem step by step:

Let's assume that the width of the rectangle is represented by "w" (in feet).

According to the given information, the length of the rectangle is 4 feet longer than its width, which means the length can be represented as "w + 4" (in feet).

The perimeter of a rectangle is calculated by adding up all the sides. In this case, the perimeter is given as 32 feet.

Since a rectangle has two pairs of equal sides (length and width), we can express the perimeter equation as the following:

2(length + width) = perimeter

Substituting the values into the equation, we get:

2(w + (w + 4)) = 32

Simplifying the equation, we have:

2(2w + 4) = 32

4w + 8 = 32

4w = 24

w = 6

Now we know that the width of the rectangle is 6 feet. To find the length, we can substitute this value back into the equation for the length:

Length = w + 4 = 6 + 4 = 10 feet

The width is 6 feet, and the length is 10 feet. Now we can calculate the area of the rectangle:

Area = Length × Width = 10 × 6 = 60 square feet

Answer: The area of the rectangle is 60 square feet.

User Davecave
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