Question

In preparing 2.50 L of 0.125 M H₂SO, solution from 18.0 M H₂SO, how much H₂O would be required?

Answer 1

Answer: 2.48 L of water is required.

Step-by-step explanation:

We will use the formula relating concentration and volume:

`M_1V_1 = M_2V_2`

From the given information, we have:

`(18.0 \text{ M})(x) = (0.125 \text{ M})(2.50 \text{ L})`

then,
`x = 0.0174 \text{ L}`. This represents the amount of stock solution required.

To find the amount of water, we simply subtract the amount of stock solution from the total volume of 2.50 L:

`V_\text{H2O} = 2.50 \text{ L} - 0.0174 \text{ L} = 2.48 \text{ L}`