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Two point charges of −1.0 × 10−6 and +2.0 × 10−6 are separated

by a distance of 0.30 . What is the electrostatic force on each
particle? Hint ( = 9.0 × 1092
−2)

1 Answer

3 votes
The electrostatic force on each particle can be calculated using Coulomb's law, which states that the force between two point charges is proportional to the product of the charges and inversely proportional to the square of the distance between them.

The formula for Coulomb's law is:
F = k * (q1 * q2) / r^2

where F is the force, k is Coulomb's constant (9.0 x 10^9 N*m^2/C^2), q1 and q2 are the charges of the two particles, and r is the distance between them.

Using this formula, we can calculate the electrostatic force on each particle:
For the particle with charge -1.0 x 10^-6 C:
F = (9.0 x 10^9 N*m^2/C^2) * (-1.0 x 10^-6 C) * (2.0 x 10^-6 C) / (0.30 m)^2
F = -6.0 x 10^-5 N

Therefore, the electrostatic force on the particle with charge -1.0 x 10^-6 C is -6.0 x 10^-5 N.

For the particle with charge +2.0 x 10^-6 C:
F = (9.0 x 10^9 N*m^2/C^2) * (2.0 x 10^-6 C) * (-1.0 x 10^-6 C) / (0.30 m)^2
F = 6.0 x 10^-5 N

Therefore, the electrostatic force on the particle with charge +2.0 x 10^-6 C is 6.0 x 10^-5 N.
User Marco Sanchez
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