Question

the binding energy per nucleon for 11 5b is about 7 mev. what is the minimum energy needed to separate the nucleons of 11 5b ?

Answer 1

The minimum energy needed to separate the nucleons of Boron-11 is 77 MeV, which is calculated by multiplying the given binding energy per nucleon (7 MeV) by the total number of nucleons (11).

Step-by-step explanation:

The minimum energy needed to separate the nucleons of Boron-11 (^{11}B) is calculated by multiplying the binding energy per nucleon by the total number of nucleons (protons and neutrons) in the nucleus. With a binding energy per nucleon of about 7 MeV for ^{11}B and a total of 11 nucleons, the minimum energy required is:

7 MeV/nucleon × 11 nucleons = 77 MeV

This value represents the minimum energy necessary to completely disassemble the nucleus into individual protons and neutrons.

Answer 2

Final answer:

The minimum energy needed to separate the nucleons of 11B is the product of the binding energy per nucleon (7 MeV) and the number of nucleons (11), resulting in a total of 77 MeV.

Step-by-step explanation:

The binding energy per nucleon of an atomic nucleus is a measure of the energy required to separate the nucleus into its individual protons and neutrons. For the isotope 11B, with a binding energy of approximately 7 MeV per nucleon, we must first calculate the total binding energy by multiplying per nucleon value by the total number of nucleons (protons plus neutrons) in the nucleus.

In the case of 11B, there are 11 nucleons in total. Therefore, the total binding energy would be:

Total Binding Energy = Binding Energy per Nucleon x Number of Nucleons

Total Binding Energy = 7 MeV/nucleon x 11 nucleons

Total Binding Energy = 77 MeV

This represents the minimum energy needed to separate all the nucleons in the 11B nucleus.