Answer:
15, 17, 19, and 21.
Step-by-step explanation:
Let the four consecutive odd numbers be x, x+2, x+4, and x+6.
The sum of these numbers is:
x + (x+2) + (x+4) + (x+6) = 72
4x + 12 = 72
4x = 60
x = 15
x+2=15+2=17
x+4=15+4=19
x+6=15+6=21
Therefore, the four consecutive odd numbers are 15, 17, 19, and 21.